C Interview Questions and Answers


How can I dynamically allocate arrays?

The equivalence between arrays and pointers allows a pointer to malloc'ed memory
to simulate an array quite effectively. After executing

#include <stdlib.h>

int *dynarray;

dynarray = malloc(10 * sizeof(int));

(and if the call to malloc succeeds), you can reference dynarray[i] (for i from
0 to 9) almost as if dynarray were a conventional, statically-allocated array (int
a[10]). The only difference is that sizeof will not give the size of the ``array''

Posted by:Richards