C Interview Questions and Answers

 

Why does the call char scanf work?

Why does the call



char s[30];



scanf("%s", s);





work? I thought you always needed an & on each variable passed to scanf.





You always need a pointer; you don't necessarily need an explicit &. When you
pass an array to scanf, you do not need the &, because arrays are always passed
to functions as pointers, whether you use & or not.

Posted by:Richards